crypto.md5 1 Report post Posted June 25, 2007 Salah tu dik.. 172.16.0.0/20255.255.240.011111111.11111111.11110000.00000000 /20setiap bit represent =128 . 64 . 32 . 16 . 8 . 4 . 2 . 1 , add semua ni jadi 255jadi kira berapa bit yang on, 11110000128 + 64 + 32 + 16 + 0 + 0 + 0 + 0 = 240 Ok, kira subnetmask yang Ehc bagi tadi172.16.0.0/12 Quote Share this post Link to post Share on other sites
slaughters 1 Report post Posted June 25, 2007 prontoxp a salah ajar aku.. hampes... Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 25, 2007 Huh? bila? sebelum thread ni wujud ke? atau selepas thread ni wujud.. kalau selepas thread ni wujud.. adoi adoi, mana pronto nih.Untuk Pronto je, Jawab ni, 172.16.10.1/18apa subnetmask niSlaughters, cari subnetmask ni 192.168.1.1/27 Quote Share this post Link to post Share on other sites
Ehc 0 Report post Posted June 25, 2007 Ok, kira subnetmask yang Ehc bagi tadi172.16.0.0/12aku pun nak cuba nasib172.16.0.0/12 8 bit . 4 bit . 0 bit . 0 bit255.240.0.0 (subnetmask)Network ID = 172.16.0.0maka pergerakan ip(255 - 255).(255-240).(255-0).(255-0) 0 . 15 . 255 . 255jadi broadcast,(172+0).(16+15).(255+0).(255+0) = 172.31.255.255jumlah ip yang boleh digunakan = (15x255x255) - 2 = 975373 ipbetul tak ? Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 25, 2007 (edited) (255 - 255).(255-240).(255-0).(255-0) 0 . 15 . 255 . 255jadi broadcast,(172+0).(16+15).(255+0).(255+0) = 172.31.255.255jumlah ip yang boleh digunakan = (15x255x255) - 2 = 975373 ipbetul tak ? aku ternampak skill menjawab terbaru..bagus2..subnet mask sama ngan aku 255.240.0.0 /1232-12=202^20=1048576-2=1048574 usable host..eh..ntahle.. Edited June 25, 2007 by mds Quote Share this post Link to post Share on other sites
slaughters 1 Report post Posted June 25, 2007 aku dah lost...tak tau lost kat mane..hahahahahahaha..tolong.... Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 25, 2007 (edited) Fuhhhh, tu dia, 1 lagi teknik pengiraan baru timbulYang ni aku setuju72.16.0.0/128 bit . 4 bit . 0 bit . 0 bit255.240.0.0 (subnetmask)Network ID = 172.16.0.0maka pergerakan ip(255 - 255).(255-240).(255-0).(255-0)0 . 15 . 255 . 255jadi broadcast,(172+0).(16+15).(255+0).(255+0) = 172.31.255.255Sampai part ni salah(15x255x255) - 2 = 975373 ipPercubaan yang bagus Slaughters, rilek, jawab soalan yang aku tujukan khas untuk ko tadi..Ingat ni128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 Edited June 25, 2007 by crypto.md5 Quote Share this post Link to post Share on other sites
Ehc 0 Report post Posted June 25, 2007 hai ya, kantoi. hehe. silap ilmu hisab la.... almaklum paper math tiga kali amik baru lepaskalau (16x256x256) - 2 = 1048574, my mistake.betul ka ? Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 25, 2007 aku ternampak skill menjawab terbaru..bagus2..subnet mask sama ngan aku 255.240.0.0 /1232-12=202^20=1048576-2=1048574 usable host..eh..ntahle.. hai ya, kantoi. hehe. silap ilmu hisab la.... almaklum paper math tiga kali amik baru lepaskalau (16x256x256) - 2 = 1048574, my mistake.betul ka ? sama ngan aku..mari tunggu cikgu crypto....cikgguuu Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 25, 2007 Lain skill ni, aku cuba cari kesilapan pada akhir pengiraannya tapi tak jumpa, betul... memang betul jawapan tu, tak syak lagi memang betul. Aku kira2 dapat jawapan yang sama guna power of 2, ni tak payah guna power pun boleh jadi jugak ehehe. Tambah satu lagi skills yang kita kumpul kat thread ni, memang bestlah korang 32-12=202^20=1048576-2=1048574 Quote Share this post Link to post Share on other sites
prontoxp 2 Report post Posted June 26, 2007 Huh? bila? sebelum thread ni wujud ke? atau selepas thread ni wujud.. kalau selepas thread ni wujud.. adoi adoi, mana pronto nih.Untuk Pronto je, Jawab ni, 172.16.10.1/18apa subnetmask niSlaughters, cari subnetmask ni 192.168.1.1/27 172.16.10.1/18 subnet mask nya 255.255.192.0 , oktet 8 , 8 , 11000000 , 00000000 Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 26, 2007 172.16.10.1/18 subnet mask nya 255.255.192.0 , oktet 8 , 8 , 11000000 , 00000000slamber tenang je prontoxp jawab..maklum ar..otai Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 26, 2007 172.16.10.1/18 subnet mask nya 255.255.192.0 , oktet 8 , 8 , 11000000 , 00000000Ok, risau aku, ingatkan dah lupa, eheheh, betul, berapa jumlah host dalam ip range ni? Quote Share this post Link to post Share on other sites
fighterama 0 Report post Posted June 26, 2007 Ok, risau aku, ingatkan dah lupa, eheheh, betul, berapa jumlah host dalam ip range ni?klau tak silap 172.16.10.1/18 subnet mask nya 255.255.192.0 = 11111111.11111111.11000000.00000000 = (14^2)-2 = 8192 -2= 8190 usable host --> tul ker nie..?? Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 26, 2007 (edited) klau tak silap 172.16.10.1/18 subnet mask nya 255.255.192.0= 11111111.11111111.11000000.00000000= (14^2)-2 = 8192 -2= 8190 usable host --> tul ker nie..??Yup, 255.255.192.0, cuma jumlah usable host ko salah, ehehe try lagi Edited June 26, 2007 by crypto.md5 Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 26, 2007 Haaaa.. baru aku ingat, slaughters, ko hutang aku satu soalan cari subnetmask 192.168.1.1/27 Quote Share this post Link to post Share on other sites
prontoxp 2 Report post Posted June 26, 2007 mat tenuk suka power 0f 2jadi nya 172.16.10.1/18 = 32 - 18 = 14 unit @ 2^14 = 16384 IP, tolak 2 ip Net ID dgn Bcast = 16382Kalo kira cara lambat255.255.192.0 255- 192 = 63 = 63x256 = 16128 0 = 25616128 + 256 = 16384 , Tolak Net Id dgn Bcast = 16382 Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 26, 2007 Haaaa.. baru aku ingat, slaughters, ko hutang aku satu soalan cari subnetmask 192.168.1.1/27hutang? slaughters jgn hutang2..tak baik woooo..mat tenuk suka power 0f 2jadi nya 172.16.10.1/18 = 32 - 18 = 14 unit @ 2^14 = 16384 IP, tolak 2 ip Net ID dgn Bcast = 16382Kalo kira cara lambat255.255.192.0 255- 192 = 63 = 63x256 = 16128 0 = 25616128 + 256 = 16384 , Tolak Net Id dgn Bcast = 16382mantap nih..dedua cara terus dia pakai..p/s:bukan niat nak spam..ni kire folo up gak nih Quote Share this post Link to post Share on other sites
Ehc 0 Report post Posted June 26, 2007 aku pun nak cuba, kalau salah tolong betulkan172.16.10.1/18 atau lebih tepat macam ni ke ? 172.16.10.0/1818 bit,8 . 8 . 2 . 0network id, 172.16.10.0subnetmask,255 . 255 . 192 . 0 pergerakan ip,(255-255).(255-255).(255-192).(255-0) 0 . 0 . 63 . 255broadcast ,(172+0).(16+0).(10+63).(0+255) = 172.16.73.255ip yang boleh digunakan(64x256) - 2 = 16382 ip yang boleh digunakan.ye ke ? Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 26, 2007 aku pun nak cuba, kalau salah tolong betulkan172.16.10.1/18 atau lebih tepat macam ni ke ? 172.16.10.0/1818 bit,8 . 8 . 2 . 0network id, 172.16.10.0subnetmask,255 . 255 . 192 . 0 pergerakan ip,(255-255).(255-255).(255-192).(255-0) 0 . 0 . 63 . 255broadcast ,(172+0).(16+0).(10+63).(0+255) = 172.16.73.255ip yang boleh digunakan(64x256) - 2 = 16382 ip yang boleh digunakan.ye ke ? jawapan sama ngan prontoxp..btol la tuh kot..tiru ke?kehkehkeh..tapi cara ko jawab tu mantap ar..len dari yg len..p/s:skali lagik, bukan niat nak spam..folo up je Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 26, 2007 (edited) Ehc, broadcast IP masih salah, jumlah host betul. tumpukan perhatian dalam pencarian broadcast IPmds, sekarang aku pun nak test ko punya knowledge setakat ni, tolong aku troubleshoot masalah ni. jangan hampakan aku ooo ya, network ID pun salah. Don't worry, kita sama2 betulkan Edited June 26, 2007 by crypto.md5 Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 26, 2007 (edited) (255-255).(255-255).(255-192).(255-0) 0 . 0 . 63 . 255broadcast ,(172+0).(16+0).(10+63).(0+255) = 172.16.73.255tak perasan broadcast id..aku pon tak try kire..pastu cakap btol..wakaka 172.16.10.0 /18 32-18=14 2^14=1638416384 /256 = 6464+10=74jadi 172.16.74.255 <--broadcast id tapi aku rasa cam 172.16.72.255 broadcast die..kire2 tak btol kot..aku pon cam telah mengeluarkan satu teknik mengira je..cikgu crypto..tatau ar camne hehemds, sekarang aku pun nak test ko punya knowledge setakat ni, tolong aku troubleshoot masalah ni. jangan hampakan aku hehe..aku cam dah menghampakan ko je.. Edited June 26, 2007 by mds Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 26, 2007 kita imbas kembali page 1, subnetting class c addres sama dengan class a & b address.Bagaimana pula dengan 192.168.4.64/27? Berapa network atau subnet yang telah dipecahkan? Takkan satu subnet dari 192.168.4.64 hingga 192.168.4.95 saja? Trick is like this:192.168.4.64/27 255.255.255.224Gunakan angka 256 tolak dengan hujung subnet 224256-224=32Tambah 32 mula dari 00 32 64 96 128 160 192 224 255Berapa subnet? Yes 8 subnet. Selain dari kira table di atas, jalan pintas ialah:/27 = 11100000 berapa on?ya 3 on. Jadi 2^3= 8 subnetYang korang kira 192.168.4.64 tadi tu ialah subnet ke 3. Keseluruhan subnet dalam network ini ialah1) 192.168.4.0 – 192.168.4.312) 192.168.4.32 – 192.168.4.633) 192.168.4.64 – 192.168.4.954) 192.168.4.96 – 192.168.4.1275) 192.168.4.128 – 192.168.4.1596) 192.168.4.160 – 192.168.4.1917) 192.168.4.192 – 192.168.4.2238) 192.168.4.224 – 192.168.4.255Jika dalam exam anda diberi soalan begini:192.168.4.170/27For the network address above, find the network ID.anda tahu yang .170 termasuk dalam golongan subnet ke 6 192.168.4.160/27 hingga 192.168.4.191/27, jadi 192.168.4.160/27 network ID dia.dan tambah explanation dari mds sendiri, page 2 post #32bagaimana kita nak tahu ip2 ini berada dalam network yg sama?cth :ip1: 192.168.1.15 /24 ip2: 192.168.1.24 /24antara cara yang aku tahu..ip ni kita and(get logik) kan dengan subnet nyeseperti yg kita tahu..ip kat atas ni dari kelas Cget logik and atau dan1 and 1 = 11 and 0 = 00 and 0 = 0tukar kepada binary 192.168.1.15 = 11000000.10101000.00000001.00001111 andsubnet 255.255.255.0 = 11111111.11111111.11111111.0000000011000000.10101000.00000001.00000000 = 192.168.1.0192.168.1.24 = 11000000.10101000.00000001.00001000 andsubnet 255.255.255.0 = 11111111.11111111.11111111.0000000011000000.10101000.00000001.00000000 =192.168.1.0try to troubleshoot sekali lagi bro... Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 26, 2007 172.16.10.1 /18256-192=640 64 128 192 256 1).172.16.0.0 - 172.16.63.255 2)172.16.64.0-172.16.191.255172.16.10.1 /18 dalam subnet 1cam ni ke?network id die 172.16.0.0..broadcast id die 172.16.63.255...ish.. Quote Share this post Link to post Share on other sites
Ehc 0 Report post Posted June 26, 2007 172.16.10.1 /18 dalam subnet 1cam ni ke?network id die 172.16.0.0..broadcast id die 172.16.63.255...ye tu kot, sebab mungkin maksud crypto, 172.16.10.1 itu adalah ip sebenarnya dan bukannya network id.kalau 172.16.0.0/18 maka betul la jawapan ko ni mds. Quote Share this post Link to post Share on other sites