crypto.md5 1 Report post Posted June 18, 2007 takdelah susah, asalkan ko faham basic VLSM, tadi tu pun ko dikira subnetting a subnet, 255.255.255.0 /24. macam2 subnet ada kat dalam. hehehe, tapi yang ni ko subnet yg /26 , /27, /28...etc , cuba ko fikir dulu macam mana. aku rasa ko akan dapat idea Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 19, 2007 aku try lagik soklan sama eh..tapi queue len..klu camni leh ke?rangkaian F 192.168.1.0 - 192.168.1.31 /27 30 host 2^5=32 0,32,64rangkaian B 192.168.1.32 - 192.168.1.35 /30 2 host 2^2=4 0,4,8,12,16,32rangkaian C 192.168.1.36 - 192.168.1.39 /30 2 host 2^2=4 0,4,8,12,16.32,36rangkaian E 192.168.1.40 - 192.168.1.43 /30 2 host 2^2=4 0,4,8,12,16,32,36,40rangkaian A 192.168.1.48 - 192.168.1.55 /29 5 host 2^3=8 0,8,16,32,40,48rangkaian D 192.168.1.64 - 192.168.1.79 /28 13 host 2^4=16 0,16,32,48,64huh..btol ark?klu salah aku bersedia nak btol kan lagik nih-perghh..pronto telah di uji oleh crypto..mesti mantap pronto nih - Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 19, 2007 Betul lah tu bro, sebenarnya aku nak upload image nih, photobucket tak dapat login, hampeh slow... kejap ehh Quote Share this post Link to post Share on other sites
prontoxp 2 Report post Posted June 19, 2007 bila masa lak aku diuji ni... kebetulan aje aku borak2 kosong dgn bro tenuk ari tu... anyway camparison yg aku guna ni direct WAN ip ... mmg nampak jelas kegunaannya.. aku pun bukan faham sgt pengiraan.. Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 19, 2007 Ni cara pengiraan aku:Satu contoh lagi VLSM, yang ni lebih canggih & lebih complex nak faham dari yang main sukat2 tu hehehe. Memandangkan dah tau VLSM, saya akan explain bagaimana subnetting a subnet.Anda diberi maklumat ini:1 Network= 125 Hosts2 Network= 30 Hosts1 Network= 14 Hosts2 Network= 5 Hosts4 Network= 2 HostsDalam semua network, host yang paling banyak ialah 125 hosts. Pecahkan network 192.168.1.0/24 jadi 2. 2^7=128, /25Kita ada 2 subnet sekarang iaitu192.168.1.0/25 – 192.168.1.127/25192.168.1.128/25 – 192.168.1.255/25Saya assign network 192.168.1.128/25 ke network yang 125 hosts. Ok yang ni setel..Host yang paling banyak 30. Jadi saya subnet lagi 192.168.1.0/25 ke /27192.168.1.0/27192.168.1.32/27 < -- saya assign ni ke network yang 30 hosts192.168.1.64/27 < -- saya assign ni ke network yang 30 hosts192.168.1.96/27Saya subnet lagi 192.168.1.0/27 jadi:192.168.1.0/28 < saya assign ni ke network yang 14 host192.168.1.16/29 < 5 hosts network192.168.1.24/29 <5 hosts networkSaya subnet 192.168.1.96/27 jadi:192.168.1.96/30 < -- 2 hosts192.168.1.100/30 < -- 2 hosts192.168.1.104/30 < -- 2 hosts192.168.1.108/30 < -- 2 hostsSekarang korang cuba:2 network = 64 hosts2 Network= 30 Hosts1 Network= 14 Hosts2 Network= 5 Hosts4 Network= 2 HostsJangan ikut aku punya sample, buat ikut citarasa tapi mesti cun & lawa Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 19, 2007 eyahhh..skli lagik aku mencuba..mana mereka2 yg len..jwab je..tgk aku lebih 5 kali percubaan baru betul jawapan..klu xm camni kan best..k..192.168.1.0 /25 <-64 host (sekiranya x termasuk network id dan broadcast id )192.168.1.128 /25 <-64 host(sekiranya x termasuk network id dan broadcast id )dari 192.168.1.0 /25 192.168.1.0 /27 192.168.1.32 /27 192.168.1.64 /27 <- assign utk 30 host 192.168.1.96 /27 <- assign utk 30 host dari 192.168.1.32 /27 192.168.1.32 /28 <- assign utk 14 host 192.168.1.48 /29 <- assign utk 5 host 192.168.1.56 /29 <- assign utk 5 host dari 192.168.1.0 /27 192.168.1.0 /30 <- assign utk 2 host 192.168.1.4 /30 <- assign utk 2 host 192.168.1.8 /30 <- assign utk 2 host 192.168.1.12 /30 <- assign utk 2 hostyahhh..sile2 komen Quote Share this post Link to post Share on other sites
brigedalaqsa 0 Report post Posted June 19, 2007 agak menarik topik nih..aku dah ikuti dari mula..bila nak masuk page ke2 aku dah mula pening..macam x susah sangat tapi entahla kenapa aku pening..tapi takpa aku akan cuba fahami sebaik mungkin..*sebenarnya masa kat UTM lagi aku x paham benda2 ni semua.. tapi masa tu memang x paham langsung.. Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 19, 2007 Page 2 tu, VLSM ke brigedalaqsa? boleh cuba soalan yg. aku bagi, kalau tak faham, mds pun boleh tolong ajarkan Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 19, 2007 agak menarik topik nih..aku dah ikuti dari mula..bila nak masuk page ke2 aku dah mula pening..macam x susah sangat tapi entahla kenapa aku pening..tapi takpa aku akan cuba fahami sebaik mungkin..*sebenarnya masa kat UTM lagi aku x paham benda2 ni semua.. tapi masa tu memang x paham langsung.. yeah..mari kita blaja sesama..aku pon tak reti..kita blasah je jawab..ko tgk aku..byk percubaan..nnt bro crypto tolong kita..brader pronto pon power gak..mari..aku nak aja?ngehehe..jwab pon kantoi..p/s: crypto..aku dah jwab yg tadi tuh..try usha..sbb aku rasa len macam..tapi tatau kat mana..bersedia nak betulkan... Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 20, 2007 Hehe, takleh jadi nih, jangan ikut sample yg aku bagi, ni menunjukkan subnetting asas masih lemah , Ok Shah, ko cuba troubleshoot, apa yang tak kena ngan soalan aku ni2 network = 64 hosts2 Network= 30 Hosts1 Network= 14 Hosts2 Network= 5 Hosts4 Network= 2 Hosts Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 20, 2007 Hehe, takleh jadi nih, jangan ikut sample yg aku bagi, ni menunjukkan subnetting asas masih lemah , Ok Shah, ko cuba troubleshoot, apa yang tak kena ngan soalan aku ni2 network = 64 hosts2 Network= 30 Hosts1 Network= 14 Hosts2 Network= 5 Hosts4 Network= 2 Hosts hehe..takleh ikut erk(dah sah aku tak reti lagik)..troubleshoot?2 network = 64 hosts ..yg ni kot..64 host ni mungkinkah usable host je? aku tgk sample ko..2 host utk usable host..tapi ko guna 4 blok..ntah le.. Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 20, 2007 Sample aku betul. Cuma soalan yang aku nak bagi 62 host tu aku tertaip 64 host. memandangkan aku dah bagi 2 network 64 hosts, kita teruskan saja dengan 64 host, what is the possible solution.aku tgk sample ko..2 host utk usable host..tapi ko guna 4 blok.. , 2 hosts? 2^2=4? betullah 4 blok, aisehhhhmen Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 20, 2007 , 2 hosts? 2^2=4? betullah 4 blok, aisehhhhmenye btol tuh..tu yg aku konpius ngan 64 host tu..aku buh bwah 128 host =/25..jawapan aku cam tiru ko ko ke?salah ar tu?tade idea len ar camne nak jawab cara len64 host...letak kat 128 la kan.. /25 Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 20, 2007 64 host...letak kat 128 la kan.. /25Yup, sebab 64 usable host, kalau 2^6=64 , tolak network ID tolak broadcast ip, jadi tinggal 62 tak cukup, tapi yang ni 64 usable IP.Cuba ko guna Class B 172.16.10.0/16, pecahkan network ni. Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 20, 2007 (edited) Class B 172.16.10.0/16... huh..besar nih..soklan ni gak?2 network 64host2 network 30host1network 14 host2 network 5 host4 network 2 host 172.16.10.0 /24 <- 256 host 172.16.10.0 /25 <- 64 host 172.16.10.128 /25 <- 64 host 172.16.11.0 /25 172.16.11.0 /25 ---> 172.16.11.0 /27 <- utk 30 host ---> 172.16.11.32 /27 <- utk 30 host ---> 172.16.11.64 /27 ---> 172.16.11.96 /27172.16.11.64 /27 ---> 172.16.11.64 /28 <- 14 host ---> 172.16.11.80 /29 <- 5 host ---> 172.16.11.88 /29 <- 5 host172.16.11.96 /27 ---> 172.16.11.96 /30 <-2 host ---> 172.16.11.100/30 <-2host ---> 172.16.11.104 /30 <- 2host ---> 172.16.11.108 /30 <- 2host bleh ka ini? lagik satu..yg aku perasan..klu nak start nih..kene start dari network yg byk host dulu erk..ke suka ati gak Edited June 20, 2007 by mds Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 20, 2007 Jap, aku makan panadol dulu ... 172.16.10.0 /25 <- 64 host172.16.10.128 /25 <- 64 hostOk, correct172.16.11.0 /25 ---> 172.16.11.0 /27 <- utk 30 host---> 172.16.11.32 /27 <- utk 30 host---> 172.16.11.64 /27---> 172.16.11.96 /27ok, cantik172.16.11.64 /27 ---> 172.16.11.64 /28 <- 14 host---> 172.16.11.80 /29 <- 5 host---> 172.16.11.88 /29 <- 5 hostok cun172.16.11.96 /27 ---> 172.16.11.96 /30 <-2 host---> 172.16.11.100 /30 <- 2host---> 172.16.11.104 /30 <- 2host---> 172.16.11.108 /30 <- 2hostCorrectYeahhhh, nilah yang aku nak, tersusun & kemas..Ko boleh start suka hati, no problem, tapi.... tak kemas. Setakat ni kita tengok, kalau kita start dari besar ke kecik, nampak lawa je network .. tu salah satu teknik untuk kekemasan dalam subnetting. Quote Share this post Link to post Share on other sites
prontoxp 2 Report post Posted June 20, 2007 Pecahan ni bergantung kepada admin dan jugak request..kalau start2 block kecik org request... boleh aje la bukak bergantung dia nak open no atas ke no bawah Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 20, 2007 fuh..akhirnya..tapikan..aku just nampak nak start dari besar ke kecik...yg dari kecik ke besar takde idea lagik..nnt nak try ar plak..or sesape leh bg contoh..aku tgh promote thread nih..hehe..post kat thread len..mana tau terbaca signature.. Quote Share this post Link to post Share on other sites
brigedalaqsa 0 Report post Posted June 20, 2007 Page 2 tu, VLSM ke brigedalaqsa? boleh cuba soalan yg. aku bagi, kalau tak faham, mds pun boleh tolong ajarkan aku dah cuba sorang2 dan betul..aku pun x paham kat mana sebenarnya aku x paham..tapi aku akan cuba pahamkan sepaham mungkin..pening kan? Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 20, 2007 aku dah cuba sorang2 dan betul..aku pun x paham kat mana sebenarnya aku x paham..tapi aku akan cuba pahamkan sepaham mungkin..pening kan?perghh..bitau ar mana ko tak paham..mana tau..aku pon tak paham pe yg ko tak phm..crypto leh bg soklan lagik..kita cuba sesama..kembali ke page 2..takpon ko try yg subnetting a subnet tuh..ko usha example,pastu try wat soklan die..sbb aku agak nampak camne subnetting a subnet tu terjadi..hehe..agak nampak setelah beberapa kali percubaan memang penin.. Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 20, 2007 (edited) Ok, esok aku setup soalan, aku pun baru dah habis pening kepala ngan pronto pasal subnetting, eheheh, rehat dulu....mana yang tak faham boleh tanya lagi Edit lagi, try bagi contoh start dari kecik ke besarsiapa2 boleh cuba, slaughters cuba? bagitaula abang mana yang tak faham tu dik..kehkehke brigedalaqsa nak try? dengan mencuba baru aku boleh nampak bahagian mana ko tak faham. Edited June 20, 2007 by crypto.md5 Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 20, 2007 Ok, esok aku setup soalan, aku pun baru dah habis pening kepala ngan pronto pasal subnetting, haaa..kospirasi besar nih..tak ajak akuh..ni mesti advance gile..tak ajak aku pon takpe..yg basic pon kantoi..hehesiapa2 boleh cuba, slaughters cuba? bagitaula abang mana yang tak faham tu dik..kehkehke brigedalaqsa nak try? dengan mencuba baru aku boleh nampak bahagian mana ko tak faham. mari2 mencuba..jom ar slaughters..try je..ibarat buat try kat luar kotak penalti, shoot..perghh..goal..eheh..brigedalaqsa jom gak..asik aku je jawab tak betol..naek segan aku..ntah2 crypto pon dah bosan n nyampah ngan aku..maklum ar..aku nih lembab sket..tapi lantak ar..dia pon asik reply je..ok ar tuh..ni aku try lagik..corner plak..dari kecik ke besar..contoh soklan sindri :2 host = 4 network9 host = 2 network29 host = 2 network61 host = 1 networkip start dari 192.168.1.0 /242 usable host 2^2=4 start dari 0,4,8,12,16192.168.1.0-3 /30 <--2 host192.168.1.4-7 /30 <--2 host192.168.1.8-11 /30 <--2 host192.168.1.12-15 /30 <--2 host9 usable host 2^4=16 0,16,32,48,64192.168.1.16-31 /28192.168.1.32-48 /2829 usable host 2^5=32 0,32,64,96,128192.168.1.64-95 /27192.168.1.96-127 /2761 usable host 2^6=64 0,64,128192.168.1.128 / 26macam aku pernah cuba je konsep camni kat mane erk?kehkehkeh..page 2..vlsm memula tu..takde idea ar camne dari kecik ke besar.. Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 21, 2007 Refer diagram kat atas. Biar saya mulakan dulu & Ignore dulu network N yang 8000 Hosts.Anda diberi network 150.150.0.0/16Network A - 4085 Hosts2^12= 4096-2= 4094 usable hosts11111111.11111111.11110000.00000000 /20255.255.240.0 256-240= 16150.150.0.0/20150.150.16.0/20 <- utk 4085 hosts150.150.32.0/20 <- utk 2040 hosts150.150.48.0/20150.150.64.0/20150.150.80.0/20150.150.96.0/20150.150.112.0/20150.150.128.0/20150.150.144.0/20150.150.160.0/20150.150.176.0/20150.150.192.0/20150.150.208.0/20150.150.224.0/20150.150.240.0/20Saya ambil network 150.150.16.0/20150.150.16.0 <- Network ID150.150.16.1 - 150.150.16.255 =255 usable ip150.150.17.0 - 150.150.17.255 =256 usable ip150.150.18.0 - 150.150.18.255 =256 usable ip150.150.19.0 - 150.150.19.255 =256 usable ip150.150.20.0 - 150.150.20.255 =256 usable ip150.150.21.0 - 150.150.21.255 =256 usable ip150.150.22.0 - 150.150.22.255 =256 usable ip150.150.23.0 - 150.150.23.255 =256 usable ip150.150.24.0 - 150.150.24.255 =256 usable ip150.150.25.0 - 150.150.25.255 =256 usable ip150.150.26.0 - 150.150.26.255 =256 usable ip150.150.27.0 - 150.150.27.255 =256 usable ip150.150.28.0 - 150.150.28.255 =256 usable ip150.150.29.0 - 150.150.29.255 =256 usable ip150.150.30.0 - 150.150.30.255 =256 usable ip150.150.31.0 - 150.150.31.254 =255 usable ip150.150.31.255 <- Broadcast IPHanya tambah usable IP, kira berapa? yes, 4094 usable ip, kira macam ni(255x2)+(256x14)= 510+3584= 4094 usable ip for host__________________________________________________________Network B - 2040 host2^11= 2048-2= 2046 Usable hosts11111111.11111111.11111000.00000000 /21255.255.248.0256-248= 8saya ambil network 150.150.32.0/20 subnet lagi kepada:150.150.32.0/21 <- utk 2040 host150.150.40.0/21150.150.32.0 <- Network ID150.150.32.1 - 150.150.32.255 =255 usable ip150.150.33.0 - 150.150.33.255 =256 usable ip150.150.34.0 - 150.150.34.255 =256 usable ip150.150.35.0 - 150.150.35.255 =256 usable ip150.150.36.0 - 150.150.36.255 =256 usable ip150.150.37.0 - 150.150.37.255 =256 usable ip150.150.38.0 - 150.150.38.255 =256 usable ip150.150.39.0 - 150.150.39.254 =255 usable ip150.150.39.255 <-Broadcast ID(255x2)+(256x6)= 510+1536= 2046 usable ipSekarang korang cuba, buat 1 persatu.p/s: mdshah paling rajin mana yang lain Quote Share this post Link to post Share on other sites
mds 0 Report post Posted June 21, 2007 150.150.0.0/20150.150.16.0/20 <- utk 4085 hosts150.150.32.0/20 <- utk 2040 hosts150.150.48.0/20aku try kat network c dulu..2000 host...2^11=2048-2=2046 usable hoststart dari 150.150.40.0 /21 utk 2000 host..150.150.40.0-network id150.150.40.1-255 usable host150.150.41.0-256 usable host150.150.42.0-256 usable host150.150.43.0-256 usable host150.150.44.0-256 usable host150.150.45.0-256 usable host150.150.46.0-256 usable host150.150.47.0-255 usable host150.150.47.255-broadcast id255*2=510 256*6=1536(510+1536)=2046yg len tu biar dulu ar..naktau yg ni btol ke tak(macam tak)..and bg peluang org len..wakaka..p/s: mdshah paling rajin mana yang lainrajin?wakakaka..nak fight ngna pronto nih..walopon pada hakikat pronto lagik power.. Quote Share this post Link to post Share on other sites
crypto.md5 1 Report post Posted June 21, 2007 Yup, betullahPronto cuba? ehehehe, testing testing Quote Share this post Link to post Share on other sites